-3(i-3)+8i=3(6+i)+5i

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Solution for -3(i-3)+8i=3(6+i)+5i equation: 



-3(i-3)+8i=3(6+i)+5i

We move all terms to the left:

-3(i-3)+8i-(3(6+i)+5i)=0

We add all the numbers together, and all the variables

-3(i-3)+8i-(3(i+6)+5i)=0

We add all the numbers together, and all the variables

8i-3(i-3)-(3(i+6)+5i)=0

We multiply parentheses

8i-3i-(3(i+6)+5i)+9=0



We calculate terms in parentheses: -(3(i+6)+5i), so:

3(i+6)+5i

We add all the numbers together, and all the variables

5i+3(i+6)

We multiply parentheses

5i+3i+18

We add all the numbers together, and all the variables

8i+18

Back to the equation:

-(8i+18)



We add all the numbers together, and all the variables

5i-(8i+18)+9=0

We get rid of parentheses

5i-8i-18+9=0

We add all the numbers together, and all the variables

-3i-9=0

We move all terms containing i to the left, all other terms to the right

-3i=9

i=9/-3

i=-3

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