-3(i-5)=2(i-5)

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Solution for -3(i-5)=2(i-5) equation:


Simplifying
-3(i + -5) = 2(i + -5)

Reorder the terms:
-3(-5 + i) = 2(i + -5)
(-5 * -3 + i * -3) = 2(i + -5)
(15 + -3i) = 2(i + -5)

Reorder the terms:
15 + -3i = 2(-5 + i)
15 + -3i = (-5 * 2 + i * 2)
15 + -3i = (-10 + 2i)

Solving
15 + -3i = -10 + 2i

Solving for variable 'i'.

Move all terms containing i to the left, all other terms to the right.

Add '-2i' to each side of the equation.
15 + -3i + -2i = -10 + 2i + -2i

Combine like terms: -3i + -2i = -5i
15 + -5i = -10 + 2i + -2i

Combine like terms: 2i + -2i = 0
15 + -5i = -10 + 0
15 + -5i = -10

Add '-15' to each side of the equation.
15 + -15 + -5i = -10 + -15

Combine like terms: 15 + -15 = 0
0 + -5i = -10 + -15
-5i = -10 + -15

Combine like terms: -10 + -15 = -25
-5i = -25

Divide each side by '-5'.
i = 5

Simplifying
i = 5

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