-3(j+2)=3

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Solution for -3(j+2)=3 equation:



-3(j+2)=3
We move all terms to the left:
-3(j+2)-(3)=0
We multiply parentheses
-3j-6-3=0
We add all the numbers together, and all the variables
-3j-9=0
We move all terms containing j to the left, all other terms to the right
-3j=9
j=9/-3
j=-3

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