-3(j+20)=j+16

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Solution for -3(j+20)=j+16 equation:



-3(j+20)=j+16
We move all terms to the left:
-3(j+20)-(j+16)=0
We multiply parentheses
-3j-(j+16)-60=0
We get rid of parentheses
-3j-j-16-60=0
We add all the numbers together, and all the variables
-4j-76=0
We move all terms containing j to the left, all other terms to the right
-4j=76
j=76/-4
j=-19

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