-3(k+2)-(-6k-4)=2k

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Solution for -3(k+2)-(-6k-4)=2k equation: 



-3(k+2)-(-6k-4)=2k

We move all terms to the left:

-3(k+2)-(-6k-4)-(2k)=0

We add all the numbers together, and all the variables

-2k-3(k+2)-(-6k-4)=0

We multiply parentheses

-2k-3k-(-6k-4)-6=0

We get rid of parentheses

-2k-3k+6k+4-6=0

We add all the numbers together, and all the variables

k-2=0

We move all terms containing k to the left, all other terms to the right

k=2

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