-3(k+2)-8=-2k+15

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Solution for -3(k+2)-8=-2k+15 equation: 



-3(k+2)-8=-2k+15

We move all terms to the left:

-3(k+2)-8-(-2k+15)=0

We multiply parentheses

-3k-(-2k+15)-6-8=0

We get rid of parentheses

-3k+2k-15-6-8=0

We add all the numbers together, and all the variables

-1k-29=0

We move all terms containing k to the left, all other terms to the right

-k=29

k=29/-1

k=-29

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