-3(k+2)-k-5=-4(k+5)+9

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Solution for -3(k+2)-k-5=-4(k+5)+9 equation: 



-3(k+2)-k-5=-4(k+5)+9

We move all terms to the left:

-3(k+2)-k-5-(-4(k+5)+9)=0

We add all the numbers together, and all the variables

-1k-3(k+2)-(-4(k+5)+9)-5=0

We multiply parentheses

-1k-3k-(-4(k+5)+9)-6-5=0



We calculate terms in parentheses: -(-4(k+5)+9), so:

-4(k+5)+9

We multiply parentheses

-4k-20+9

We add all the numbers together, and all the variables

-4k-11

Back to the equation:

-(-4k-11)



We add all the numbers together, and all the variables

-4k-(-4k-11)-11=0

We get rid of parentheses

-4k+4k+11-11=0

We add all the numbers together, and all the variables

=0

k=0/1

k=0

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