-3(k+2)=3k-6

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Solution for -3(k+2)=3k-6 equation: 



-3(k+2)=3k-6

We move all terms to the left:

-3(k+2)-(3k-6)=0

We multiply parentheses

-3k-(3k-6)-6=0

We get rid of parentheses

-3k-3k+6-6=0

We add all the numbers together, and all the variables

-6k=0

k=0/-6

k=0

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