-3(k+4)=10(4-2k)+4k

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Solution for -3(k+4)=10(4-2k)+4k equation: 



-3(k+4)=10(4-2k)+4k

We move all terms to the left:

-3(k+4)-(10(4-2k)+4k)=0

We add all the numbers together, and all the variables

-3(k+4)-(10(-2k+4)+4k)=0

We multiply parentheses

-3k-(10(-2k+4)+4k)-12=0



We calculate terms in parentheses: -(10(-2k+4)+4k), so:

10(-2k+4)+4k

We add all the numbers together, and all the variables

4k+10(-2k+4)

We multiply parentheses

4k-20k+40

We add all the numbers together, and all the variables

-16k+40

Back to the equation:

-(-16k+40)



We get rid of parentheses

-3k+16k-40-12=0

We add all the numbers together, and all the variables

13k-52=0

We move all terms containing k to the left, all other terms to the right

13k=52

k=52/13

k=4

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