-3(k+5)=2(-3k-11)

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Solution for -3(k+5)=2(-3k-11) equation: 



-3(k+5)=2(-3k-11)

We move all terms to the left:

-3(k+5)-(2(-3k-11))=0

We multiply parentheses

-3k-(2(-3k-11))-15=0



We calculate terms in parentheses: -(2(-3k-11)), so:

2(-3k-11)

We multiply parentheses

-6k-22

Back to the equation:

-(-6k-22)



We get rid of parentheses

-3k+6k+22-15=0

We add all the numbers together, and all the variables

3k+7=0

We move all terms containing k to the left, all other terms to the right

3k=-7

k=-7/3

k=-2+1/3

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