-3(k-1)=3(k+1)-48

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Solution for -3(k-1)=3(k+1)-48 equation: 



-3(k-1)=3(k+1)-48

We move all terms to the left:

-3(k-1)-(3(k+1)-48)=0

We multiply parentheses

-3k-(3(k+1)-48)+3=0



We calculate terms in parentheses: -(3(k+1)-48), so:

3(k+1)-48

We multiply parentheses

3k+3-48

We add all the numbers together, and all the variables

3k-45

Back to the equation:

-(3k-45)



We get rid of parentheses

-3k-3k+45+3=0

We add all the numbers together, and all the variables

-6k+48=0

We move all terms containing k to the left, all other terms to the right

-6k=-48

k=-48/-6

k=+8

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