-3(k-2)=2(-3k+9)-6

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Solution for -3(k-2)=2(-3k+9)-6 equation: 



-3(k-2)=2(-3k+9)-6

We move all terms to the left:

-3(k-2)-(2(-3k+9)-6)=0

We multiply parentheses

-3k-(2(-3k+9)-6)+6=0



We calculate terms in parentheses: -(2(-3k+9)-6), so:

2(-3k+9)-6

We multiply parentheses

-6k+18-6

We add all the numbers together, and all the variables

-6k+12

Back to the equation:

-(-6k+12)



We get rid of parentheses

-3k+6k-12+6=0

We add all the numbers together, and all the variables

3k-6=0

We move all terms containing k to the left, all other terms to the right

3k=6

k=6/3

k=2

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