-3(k-6)+k=-4(1+k)

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Solution for -3(k-6)+k=-4(1+k) equation:



-3(k-6)+k=-4(1+k)
We move all terms to the left:
-3(k-6)+k-(-4(1+k))=0
We add all the numbers together, and all the variables
-3(k-6)+k-(-4(k+1))=0
We add all the numbers together, and all the variables
k-3(k-6)-(-4(k+1))=0
We multiply parentheses
k-3k-(-4(k+1))+18=0
We calculate terms in parentheses: -(-4(k+1)), so:
-4(k+1)
We multiply parentheses
-4k-4
Back to the equation:
-(-4k-4)
We add all the numbers together, and all the variables
-2k-(-4k-4)+18=0
We get rid of parentheses
-2k+4k+4+18=0
We add all the numbers together, and all the variables
2k+22=0
We move all terms containing k to the left, all other terms to the right
2k=-22
k=-22/2
k=-11

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