-3(n+4)+n=-2(n+6)

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Solution for -3(n+4)+n=-2(n+6) equation: 



-3(n+4)+n=-2(n+6)

We move all terms to the left:

-3(n+4)+n-(-2(n+6))=0

We add all the numbers together, and all the variables

n-3(n+4)-(-2(n+6))=0

We multiply parentheses

n-3n-(-2(n+6))-12=0



We calculate terms in parentheses: -(-2(n+6)), so:

-2(n+6)

We multiply parentheses

-2n-12

Back to the equation:

-(-2n-12)



We add all the numbers together, and all the variables

-2n-(-2n-12)-12=0

We get rid of parentheses

-2n+2n+12-12=0

We add all the numbers together, and all the variables

=0

n=0/1

n=0

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