-3(n-2)-n=4(4-n)+5

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Solution for -3(n-2)-n=4(4-n)+5 equation: 



-3(n-2)-n=4(4-n)+5

We move all terms to the left:

-3(n-2)-n-(4(4-n)+5)=0

We add all the numbers together, and all the variables

-3(n-2)-n-(4(-1n+4)+5)=0

We add all the numbers together, and all the variables

-1n-3(n-2)-(4(-1n+4)+5)=0

We multiply parentheses

-1n-3n-(4(-1n+4)+5)+6=0



We calculate terms in parentheses: -(4(-1n+4)+5), so:

4(-1n+4)+5

We multiply parentheses

-4n+16+5

We add all the numbers together, and all the variables

-4n+21

Back to the equation:

-(-4n+21)



We add all the numbers together, and all the variables

-4n-(-4n+21)+6=0

We get rid of parentheses

-4n+4n-21+6=0

We add all the numbers together, and all the variables

-15!=0

There is no solution for this equation

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