-3(n-4)+5=32+2n

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Solution for -3(n-4)+5=32+2n equation: 



-3(n-4)+5=32+2n

We move all terms to the left:

-3(n-4)+5-(32+2n)=0

We add all the numbers together, and all the variables

-3(n-4)-(2n+32)+5=0

We multiply parentheses

-3n-(2n+32)+12+5=0

We get rid of parentheses

-3n-2n-32+12+5=0

We add all the numbers together, and all the variables

-5n-15=0

We move all terms containing n to the left, all other terms to the right

-5n=15

n=15/-5

n=-3

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