-3(n-4)-(4n-1)=-3+(3n-1)

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Solution for -3(n-4)-(4n-1)=-3+(3n-1) equation: 



-3(n-4)-(4n-1)=-3+(3n-1)

We move all terms to the left:

-3(n-4)-(4n-1)-(-3+(3n-1))=0

We multiply parentheses

-3n-(4n-1)-(-3+(3n-1))+12=0

We get rid of parentheses

-3n-4n-(-3+(3n-1))+1+12=0



We calculate terms in parentheses: -(-3+(3n-1)), so:

-3+(3n-1)

determiningTheFunctionDomain
(3n-1)-3

We get rid of parentheses

3n-1-3

We add all the numbers together, and all the variables

3n-4

Back to the equation:

-(3n-4)



We add all the numbers together, and all the variables

-7n-(3n-4)+13=0

We get rid of parentheses

-7n-3n+4+13=0

We add all the numbers together, and all the variables

-10n+17=0

We move all terms containing n to the left, all other terms to the right

-10n=-17

n=-17/-10

n=1+7/10

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