-3(n-5)-(3n-7)=-4+(4n-2)

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Solution for -3(n-5)-(3n-7)=-4+(4n-2) equation: 



-3(n-5)-(3n-7)=-4+(4n-2)

We move all terms to the left:

-3(n-5)-(3n-7)-(-4+(4n-2))=0

We multiply parentheses

-3n-(3n-7)-(-4+(4n-2))+15=0

We get rid of parentheses

-3n-3n-(-4+(4n-2))+7+15=0



We calculate terms in parentheses: -(-4+(4n-2)), so:

-4+(4n-2)

determiningTheFunctionDomain
(4n-2)-4

We get rid of parentheses

4n-2-4

We add all the numbers together, and all the variables

4n-6

Back to the equation:

-(4n-6)



We add all the numbers together, and all the variables

-6n-(4n-6)+22=0

We get rid of parentheses

-6n-4n+6+22=0

We add all the numbers together, and all the variables

-10n+28=0

We move all terms containing n to the left, all other terms to the right

-10n=-28

n=-28/-10

n=2+4/5

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