-3(n-5)=4(1-3n)

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Solution for -3(n-5)=4(1-3n) equation: 



-3(n-5)=4(1-3n)

We move all terms to the left:

-3(n-5)-(4(1-3n))=0

We add all the numbers together, and all the variables

-3(n-5)-(4(-3n+1))=0

We multiply parentheses

-3n-(4(-3n+1))+15=0



We calculate terms in parentheses: -(4(-3n+1)), so:

4(-3n+1)

We multiply parentheses

-12n+4

Back to the equation:

-(-12n+4)



We get rid of parentheses

-3n+12n-4+15=0

We add all the numbers together, and all the variables

9n+11=0

We move all terms containing n to the left, all other terms to the right

9n=-11

n=-11/9

n=-1+2/9

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