-3(n-5)=4(1-3n)

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Solution for -3(n-5)=4(1-3n) equation:



-3(n-5)=4(1-3n)
We move all terms to the left:
-3(n-5)-(4(1-3n))=0
We add all the numbers together, and all the variables
-3(n-5)-(4(-3n+1))=0
We multiply parentheses
-3n-(4(-3n+1))+15=0
We calculate terms in parentheses: -(4(-3n+1)), so:
4(-3n+1)
We multiply parentheses
-12n+4
Back to the equation:
-(-12n+4)
We get rid of parentheses
-3n+12n-4+15=0
We add all the numbers together, and all the variables
9n+11=0
We move all terms containing n to the left, all other terms to the right
9n=-11
n=-11/9
n=-1+2/9

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