-3(r+6)=-3(12-3r)-10r

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Solution for -3(r+6)=-3(12-3r)-10r equation: 



-3(r+6)=-3(12-3r)-10r

We move all terms to the left:

-3(r+6)-(-3(12-3r)-10r)=0

We add all the numbers together, and all the variables

-3(r+6)-(-3(-3r+12)-10r)=0

We multiply parentheses

-3r-(-3(-3r+12)-10r)-18=0



We calculate terms in parentheses: -(-3(-3r+12)-10r), so:

-3(-3r+12)-10r

We add all the numbers together, and all the variables

-10r-3(-3r+12)

We multiply parentheses

-10r+9r-36

We add all the numbers together, and all the variables

-1r-36

Back to the equation:

-(-1r-36)



We get rid of parentheses

-3r+1r+36-18=0

We add all the numbers together, and all the variables

-2r+18=0

We move all terms containing r to the left, all other terms to the right

-2r=-18

r=-18/-2

r=+9

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