-3(r-12)+15=2(r-2)

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Solution for -3(r-12)+15=2(r-2) equation:



-3(r-12)+15=2(r-2)
We move all terms to the left:
-3(r-12)+15-(2(r-2))=0
We multiply parentheses
-3r-(2(r-2))+36+15=0
We calculate terms in parentheses: -(2(r-2)), so:
2(r-2)
We multiply parentheses
2r-4
Back to the equation:
-(2r-4)
We add all the numbers together, and all the variables
-3r-(2r-4)+51=0
We get rid of parentheses
-3r-2r+4+51=0
We add all the numbers together, and all the variables
-5r+55=0
We move all terms containing r to the left, all other terms to the right
-5r=-55
r=-55/-5
r=+11

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