-3(r-2)-r=4(-2+2r)-5r

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Solution for -3(r-2)-r=4(-2+2r)-5r equation: 



-3(r-2)-r=4(-2+2r)-5r

We move all terms to the left:

-3(r-2)-r-(4(-2+2r)-5r)=0

We add all the numbers together, and all the variables

-3(r-2)-r-(4(2r-2)-5r)=0

We add all the numbers together, and all the variables

-1r-3(r-2)-(4(2r-2)-5r)=0

We multiply parentheses

-1r-3r-(4(2r-2)-5r)+6=0



We calculate terms in parentheses: -(4(2r-2)-5r), so:

4(2r-2)-5r

We add all the numbers together, and all the variables

-5r+4(2r-2)

We multiply parentheses

-5r+8r-8

We add all the numbers together, and all the variables

3r-8

Back to the equation:

-(3r-8)



We add all the numbers together, and all the variables

-4r-(3r-8)+6=0

We get rid of parentheses

-4r-3r+8+6=0

We add all the numbers together, and all the variables

-7r+14=0

We move all terms containing r to the left, all other terms to the right

-7r=-14

r=-14/-7

r=+2

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