-3(r-5)=33+6r

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Solution for -3(r-5)=33+6r equation: 



-3(r-5)=33+6r

We move all terms to the left:

-3(r-5)-(33+6r)=0

We add all the numbers together, and all the variables

-3(r-5)-(6r+33)=0

We multiply parentheses

-3r-(6r+33)+15=0

We get rid of parentheses

-3r-6r-33+15=0

We add all the numbers together, and all the variables

-9r-18=0

We move all terms containing r to the left, all other terms to the right

-9r=18

r=18/-9

r=-2

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