-3(t-3)+7t=9t-2

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Solution for -3(t-3)+7t=9t-2 equation: 



-3(t-3)+7t=9t-2

We move all terms to the left:

-3(t-3)+7t-(9t-2)=0

We add all the numbers together, and all the variables

7t-3(t-3)-(9t-2)=0

We multiply parentheses

7t-3t-(9t-2)+9=0

We get rid of parentheses

7t-3t-9t+2+9=0

We add all the numbers together, and all the variables

-5t+11=0

We move all terms containing t to the left, all other terms to the right

-5t=-11

t=-11/-5

t=2+1/5

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