-3(t-3)-2(2t+1)=-8

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Solution for -3(t-3)-2(2t+1)=-8 equation: 



-3(t-3)-2(2t+1)=-8

We move all terms to the left:

-3(t-3)-2(2t+1)-(-8)=0

We add all the numbers together, and all the variables

-3(t-3)-2(2t+1)+8=0

We multiply parentheses

-3t-4t+9-2+8=0

We add all the numbers together, and all the variables

-7t+15=0

We move all terms containing t to the left, all other terms to the right

-7t=-15

t=-15/-7

t=2+1/7

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