-3(t-5)+7t=6t-2

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Solution for -3(t-5)+7t=6t-2 equation: 



-3(t-5)+7t=6t-2

We move all terms to the left:

-3(t-5)+7t-(6t-2)=0

We add all the numbers together, and all the variables

7t-3(t-5)-(6t-2)=0

We multiply parentheses

7t-3t-(6t-2)+15=0

We get rid of parentheses

7t-3t-6t+2+15=0

We add all the numbers together, and all the variables

-2t+17=0

We move all terms containing t to the left, all other terms to the right

-2t=-17

t=-17/-2

t=8+1/2

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