-3(t-8)-(t+2)=10

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Solution for -3(t-8)-(t+2)=10 equation: 



-3(t-8)-(t+2)=10

We move all terms to the left:

-3(t-8)-(t+2)-(10)=0

We multiply parentheses

-3t-(t+2)+24-10=0

We get rid of parentheses

-3t-t-2+24-10=0

We add all the numbers together, and all the variables

-4t+12=0

We move all terms containing t to the left, all other terms to the right

-4t=-12

t=-12/-4

t=+3

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