-3(u+1)+u=4(u+1)-5

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Solution for -3(u+1)+u=4(u+1)-5 equation: 



-3(u+1)+u=4(u+1)-5

We move all terms to the left:

-3(u+1)+u-(4(u+1)-5)=0

We add all the numbers together, and all the variables

u-3(u+1)-(4(u+1)-5)=0

We multiply parentheses

u-3u-(4(u+1)-5)-3=0



We calculate terms in parentheses: -(4(u+1)-5), so:

4(u+1)-5

We multiply parentheses

4u+4-5

We add all the numbers together, and all the variables

4u-1

Back to the equation:

-(4u-1)



We add all the numbers together, and all the variables

-2u-(4u-1)-3=0

We get rid of parentheses

-2u-4u+1-3=0

We add all the numbers together, and all the variables

-6u-2=0

We move all terms containing u to the left, all other terms to the right

-6u=2

u=2/-6

u=-1/3

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