-3(u+1)=6u-3+3(2u+6)

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Solution for -3(u+1)=6u-3+3(2u+6) equation: 



-3(u+1)=6u-3+3(2u+6)

We move all terms to the left:

-3(u+1)-(6u-3+3(2u+6))=0

We multiply parentheses

-3u-(6u-3+3(2u+6))-3=0



We calculate terms in parentheses: -(6u-3+3(2u+6)), so:

6u-3+3(2u+6)

determiningTheFunctionDomain
6u+3(2u+6)-3

We multiply parentheses

6u+6u+18-3

We add all the numbers together, and all the variables

12u+15

Back to the equation:

-(12u+15)



We get rid of parentheses

-3u-12u-15-3=0

We add all the numbers together, and all the variables

-15u-18=0

We move all terms containing u to the left, all other terms to the right

-15u=18

u=18/-15

u=-1+1/5

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