-3(u+1)=u-7+4(3u+3)

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Solution for -3(u+1)=u-7+4(3u+3) equation:



-3(u+1)=u-7+4(3u+3)
We move all terms to the left:
-3(u+1)-(u-7+4(3u+3))=0
We multiply parentheses
-3u-(u-7+4(3u+3))-3=0
We calculate terms in parentheses: -(u-7+4(3u+3)), so:
u-7+4(3u+3)
determiningTheFunctionDomain u+4(3u+3)-7
We multiply parentheses
u+12u+12-7
We add all the numbers together, and all the variables
13u+5
Back to the equation:
-(13u+5)
We get rid of parentheses
-3u-13u-5-3=0
We add all the numbers together, and all the variables
-16u-8=0
We move all terms containing u to the left, all other terms to the right
-16u=8
u=8/-16
u=-1/2

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