-3(u+10)=3u+12

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Solution for -3(u+10)=3u+12 equation: 



-3(u+10)=3u+12

We move all terms to the left:

-3(u+10)-(3u+12)=0

We multiply parentheses

-3u-(3u+12)-30=0

We get rid of parentheses

-3u-3u-12-30=0

We add all the numbers together, and all the variables

-6u-42=0

We move all terms containing u to the left, all other terms to the right

-6u=42

u=42/-6

u=-7

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