-3(u+2)+u=4(u-1)+10

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Solution for -3(u+2)+u=4(u-1)+10 equation: 



-3(u+2)+u=4(u-1)+10

We move all terms to the left:

-3(u+2)+u-(4(u-1)+10)=0

We add all the numbers together, and all the variables

u-3(u+2)-(4(u-1)+10)=0

We multiply parentheses

u-3u-(4(u-1)+10)-6=0



We calculate terms in parentheses: -(4(u-1)+10), so:

4(u-1)+10

We multiply parentheses

4u-4+10

We add all the numbers together, and all the variables

4u+6

Back to the equation:

-(4u+6)



We add all the numbers together, and all the variables

-2u-(4u+6)-6=0

We get rid of parentheses

-2u-4u-6-6=0

We add all the numbers together, and all the variables

-6u-12=0

We move all terms containing u to the left, all other terms to the right

-6u=12

u=12/-6

u=-2

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