-3(u+2)=-3(6u-1)+3u

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Solution for -3(u+2)=-3(6u-1)+3u equation: 



-3(u+2)=-3(6u-1)+3u

We move all terms to the left:

-3(u+2)-(-3(6u-1)+3u)=0

We multiply parentheses

-3u-(-3(6u-1)+3u)-6=0



We calculate terms in parentheses: -(-3(6u-1)+3u), so:

-3(6u-1)+3u

We add all the numbers together, and all the variables

3u-3(6u-1)

We multiply parentheses

3u-18u+3

We add all the numbers together, and all the variables

-15u+3

Back to the equation:

-(-15u+3)



We get rid of parentheses

-3u+15u-3-6=0

We add all the numbers together, and all the variables

12u-9=0

We move all terms containing u to the left, all other terms to the right

12u=9

u=9/12

u=3/4

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