-3(u+2)=-4(2u-3)+9u

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Solution for -3(u+2)=-4(2u-3)+9u equation: 



-3(u+2)=-4(2u-3)+9u

We move all terms to the left:

-3(u+2)-(-4(2u-3)+9u)=0

We multiply parentheses

-3u-(-4(2u-3)+9u)-6=0



We calculate terms in parentheses: -(-4(2u-3)+9u), so:

-4(2u-3)+9u

We add all the numbers together, and all the variables

9u-4(2u-3)

We multiply parentheses

9u-8u+12

We add all the numbers together, and all the variables

u+12

Back to the equation:

-(u+12)



We get rid of parentheses

-3u-u-12-6=0

We add all the numbers together, and all the variables

-4u-18=0

We move all terms containing u to the left, all other terms to the right

-4u=18

u=18/-4

u=-4+1/2

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