-3(u+2)=4u-41

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Solution for -3(u+2)=4u-41 equation:



-3(u+2)=4u-41
We move all terms to the left:
-3(u+2)-(4u-41)=0
We multiply parentheses
-3u-(4u-41)-6=0
We get rid of parentheses
-3u-4u+41-6=0
We add all the numbers together, and all the variables
-7u+35=0
We move all terms containing u to the left, all other terms to the right
-7u=-35
u=-35/-7
u=+5

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