-3(u+2)=7u-8+4(2u+1)

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Solution for -3(u+2)=7u-8+4(2u+1) equation: 



-3(u+2)=7u-8+4(2u+1)

We move all terms to the left:

-3(u+2)-(7u-8+4(2u+1))=0

We multiply parentheses

-3u-(7u-8+4(2u+1))-6=0



We calculate terms in parentheses: -(7u-8+4(2u+1)), so:

7u-8+4(2u+1)

determiningTheFunctionDomain
7u+4(2u+1)-8

We multiply parentheses

7u+8u+4-8

We add all the numbers together, and all the variables

15u-4

Back to the equation:

-(15u-4)



We get rid of parentheses

-3u-15u+4-6=0

We add all the numbers together, and all the variables

-18u-2=0

We move all terms containing u to the left, all other terms to the right

-18u=2

u=2/-18

u=-1/9

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