-3(u+3)=9u-7+2(2u+5)

Solution for -3(u+3)=9u-7+2(2u+5) equation:

-3(u+3)=9u-7+2(2u+5)

We move all terms to the left:

-3(u+3)-(9u-7+2(2u+5))=0

We multiply parentheses

-3u-(9u-7+2(2u+5))-9=0


We calculate terms in parentheses: -(9u-7+2(2u+5)), so:

9u-7+2(2u+5)

determiningTheFunctionDomain
9u+2(2u+5)-7

We multiply parentheses

9u+4u+10-7

We add all the numbers together, and all the variables

13u+3

Back to the equation:

-(13u+3)


We get rid of parentheses

-3u-13u-3-9=0

We add all the numbers together, and all the variables

-16u-12=0

We move all terms containing u to the left, all other terms to the right

-16u=12

u=12/-16

u=-3/4