-3(u+3)=u-5+2(3u+6)

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Solution for -3(u+3)=u-5+2(3u+6) equation: 



-3(u+3)=u-5+2(3u+6)

We move all terms to the left:

-3(u+3)-(u-5+2(3u+6))=0

We multiply parentheses

-3u-(u-5+2(3u+6))-9=0



We calculate terms in parentheses: -(u-5+2(3u+6)), so:

u-5+2(3u+6)

determiningTheFunctionDomain
u+2(3u+6)-5

We multiply parentheses

u+6u+12-5

We add all the numbers together, and all the variables

7u+7

Back to the equation:

-(7u+7)



We get rid of parentheses

-3u-7u-7-9=0

We add all the numbers together, and all the variables

-10u-16=0

We move all terms containing u to the left, all other terms to the right

-10u=16

u=16/-10

u=-1+3/5

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