-3(u+4)=3u-6+2(4u+3)

Solution for -3(u+4)=3u-6+2(4u+3) equation:

-3(u+4)=3u-6+2(4u+3)

We move all terms to the left:

-3(u+4)-(3u-6+2(4u+3))=0

We multiply parentheses

-3u-(3u-6+2(4u+3))-12=0


We calculate terms in parentheses: -(3u-6+2(4u+3)), so:

3u-6+2(4u+3)

determiningTheFunctionDomain
3u+2(4u+3)-6

We multiply parentheses

3u+8u+6-6

We add all the numbers together, and all the variables

11u

Back to the equation:

-(11u)


We add all the numbers together, and all the variables

-14u-12=0

We move all terms containing u to the left, all other terms to the right

-14u=12

u=12/-14

u=-6/7