-3(u+4)=u-4+6(2u+1)

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Solution for -3(u+4)=u-4+6(2u+1) equation: 



-3(u+4)=u-4+6(2u+1)

We move all terms to the left:

-3(u+4)-(u-4+6(2u+1))=0

We multiply parentheses

-3u-(u-4+6(2u+1))-12=0



We calculate terms in parentheses: -(u-4+6(2u+1)), so:

u-4+6(2u+1)

determiningTheFunctionDomain
u+6(2u+1)-4

We multiply parentheses

u+12u+6-4

We add all the numbers together, and all the variables

13u+2

Back to the equation:

-(13u+2)



We get rid of parentheses

-3u-13u-2-12=0

We add all the numbers together, and all the variables

-16u-14=0

We move all terms containing u to the left, all other terms to the right

-16u=14

u=14/-16

u=-7/8

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