-3(u+5)=7u-6+3(2u+1)

Solution for -3(u+5)=7u-6+3(2u+1) equation:

-3(u+5)=7u-6+3(2u+1)

We move all terms to the left:

-3(u+5)-(7u-6+3(2u+1))=0

We multiply parentheses

-3u-(7u-6+3(2u+1))-15=0


We calculate terms in parentheses: -(7u-6+3(2u+1)), so:

7u-6+3(2u+1)

determiningTheFunctionDomain
7u+3(2u+1)-6

We multiply parentheses

7u+6u+3-6

We add all the numbers together, and all the variables

13u-3

Back to the equation:

-(13u-3)


We get rid of parentheses

-3u-13u+3-15=0

We add all the numbers together, and all the variables

-16u-12=0

We move all terms containing u to the left, all other terms to the right

-16u=12

u=12/-16

u=-3/4