-3(v+2)=-2(4v-2)+9v

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Solution for -3(v+2)=-2(4v-2)+9v equation: 



-3(v+2)=-2(4v-2)+9v

We move all terms to the left:

-3(v+2)-(-2(4v-2)+9v)=0

We multiply parentheses

-3v-(-2(4v-2)+9v)-6=0



We calculate terms in parentheses: -(-2(4v-2)+9v), so:

-2(4v-2)+9v

We add all the numbers together, and all the variables

9v-2(4v-2)

We multiply parentheses

9v-8v+4

We add all the numbers together, and all the variables

v+4

Back to the equation:

-(v+4)



We get rid of parentheses

-3v-v-4-6=0

We add all the numbers together, and all the variables

-4v-10=0

We move all terms containing v to the left, all other terms to the right

-4v=10

v=10/-4

v=-2+1/2

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