-3(v+2)=5v-2+2(2v+2)

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Solution for -3(v+2)=5v-2+2(2v+2) equation: 



-3(v+2)=5v-2+2(2v+2)

We move all terms to the left:

-3(v+2)-(5v-2+2(2v+2))=0

We multiply parentheses

-3v-(5v-2+2(2v+2))-6=0



We calculate terms in parentheses: -(5v-2+2(2v+2)), so:

5v-2+2(2v+2)

determiningTheFunctionDomain
5v+2(2v+2)-2

We multiply parentheses

5v+4v+4-2

We add all the numbers together, and all the variables

9v+2

Back to the equation:

-(9v+2)



We get rid of parentheses

-3v-9v-2-6=0

We add all the numbers together, and all the variables

-12v-8=0

We move all terms containing v to the left, all other terms to the right

-12v=8

v=8/-12

v=-2/3

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