-3(v+2)=v-4+6(2v+1)

Solution for -3(v+2)=v-4+6(2v+1) equation:

-3(v+2)=v-4+6(2v+1)

We move all terms to the left:

-3(v+2)-(v-4+6(2v+1))=0

We multiply parentheses

-3v-(v-4+6(2v+1))-6=0


We calculate terms in parentheses: -(v-4+6(2v+1)), so:

v-4+6(2v+1)

determiningTheFunctionDomain
v+6(2v+1)-4

We multiply parentheses

v+12v+6-4

We add all the numbers together, and all the variables

13v+2

Back to the equation:

-(13v+2)


We get rid of parentheses

-3v-13v-2-6=0

We add all the numbers together, and all the variables

-16v-8=0

We move all terms containing v to the left, all other terms to the right

-16v=8

v=8/-16

v=-1/2