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-3(v+3)=3v-9+2(4v+2)
We move all terms to the left:
-3(v+3)-(3v-9+2(4v+2))=0
We multiply parentheses
-3v-(3v-9+2(4v+2))-9=0
We calculate terms in parentheses: -(3v-9+2(4v+2)), so:We get rid of parentheses
3v-9+2(4v+2)
determiningTheFunctionDomain 3v+2(4v+2)-9
We multiply parentheses
3v+8v+4-9
We add all the numbers together, and all the variables
11v-5
Back to the equation:
-(11v-5)
-3v-11v+5-9=0
We add all the numbers together, and all the variables
-14v-4=0
We move all terms containing v to the left, all other terms to the right
-14v=4
v=4/-14
v=-2/7
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