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-3(v+3)=v-7+2(4v+1)
We move all terms to the left:
-3(v+3)-(v-7+2(4v+1))=0
We multiply parentheses
-3v-(v-7+2(4v+1))-9=0
We calculate terms in parentheses: -(v-7+2(4v+1)), so:We get rid of parentheses
v-7+2(4v+1)
determiningTheFunctionDomain v+2(4v+1)-7
We multiply parentheses
v+8v+2-7
We add all the numbers together, and all the variables
9v-5
Back to the equation:
-(9v-5)
-3v-9v+5-9=0
We add all the numbers together, and all the variables
-12v-4=0
We move all terms containing v to the left, all other terms to the right
-12v=4
v=4/-12
v=-1/3
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