-3(v+4)-2v=2(v-1)

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Solution for -3(v+4)-2v=2(v-1) equation: 



-3(v+4)-2v=2(v-1)

We move all terms to the left:

-3(v+4)-2v-(2(v-1))=0

We add all the numbers together, and all the variables

-2v-3(v+4)-(2(v-1))=0

We multiply parentheses

-2v-3v-(2(v-1))-12=0



We calculate terms in parentheses: -(2(v-1)), so:

2(v-1)

We multiply parentheses

2v-2

Back to the equation:

-(2v-2)



We add all the numbers together, and all the variables

-5v-(2v-2)-12=0

We get rid of parentheses

-5v-2v+2-12=0

We add all the numbers together, and all the variables

-7v-10=0

We move all terms containing v to the left, all other terms to the right

-7v=10

v=10/-7

v=-1+3/7

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