-3(v+4)=3v-4+2(2v+3)

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Solution for -3(v+4)=3v-4+2(2v+3) equation: 



-3(v+4)=3v-4+2(2v+3)

We move all terms to the left:

-3(v+4)-(3v-4+2(2v+3))=0

We multiply parentheses

-3v-(3v-4+2(2v+3))-12=0



We calculate terms in parentheses: -(3v-4+2(2v+3)), so:

3v-4+2(2v+3)

determiningTheFunctionDomain
3v+2(2v+3)-4

We multiply parentheses

3v+4v+6-4

We add all the numbers together, and all the variables

7v+2

Back to the equation:

-(7v+2)



We get rid of parentheses

-3v-7v-2-12=0

We add all the numbers together, and all the variables

-10v-14=0

We move all terms containing v to the left, all other terms to the right

-10v=14

v=14/-10

v=-1+2/5

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