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-3(v+5)=2v-9+2(5v+6)
We move all terms to the left:
-3(v+5)-(2v-9+2(5v+6))=0
We multiply parentheses
-3v-(2v-9+2(5v+6))-15=0
We calculate terms in parentheses: -(2v-9+2(5v+6)), so:We get rid of parentheses
2v-9+2(5v+6)
determiningTheFunctionDomain 2v+2(5v+6)-9
We multiply parentheses
2v+10v+12-9
We add all the numbers together, and all the variables
12v+3
Back to the equation:
-(12v+3)
-3v-12v-3-15=0
We add all the numbers together, and all the variables
-15v-18=0
We move all terms containing v to the left, all other terms to the right
-15v=18
v=18/-15
v=-1+1/5
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