-3(v+5)=9v-9+2(2v+2)

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Solution for -3(v+5)=9v-9+2(2v+2) equation: 



-3(v+5)=9v-9+2(2v+2)

We move all terms to the left:

-3(v+5)-(9v-9+2(2v+2))=0

We multiply parentheses

-3v-(9v-9+2(2v+2))-15=0



We calculate terms in parentheses: -(9v-9+2(2v+2)), so:

9v-9+2(2v+2)

determiningTheFunctionDomain
9v+2(2v+2)-9

We multiply parentheses

9v+4v+4-9

We add all the numbers together, and all the variables

13v-5

Back to the equation:

-(13v-5)



We get rid of parentheses

-3v-13v+5-15=0

We add all the numbers together, and all the variables

-16v-10=0

We move all terms containing v to the left, all other terms to the right

-16v=10

v=10/-16

v=-5/8

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